Finding Total 3 digit Numbers Divisible by 7 Using Nth term Formula of Arithmetic Sequences
In this video lesson we are going to find the total 3 digit numbers divisible by 7. Wow 1 It looks nice.
Well to find the total number of 3 digit number divisible 7 , there are many methods but here will learn the method of Arithmetic Sequence. We will make an sequence of 3 digit number which are divisible by three then by the application of arithmetic properties we will solve the problem.
Here is the video lesson of it. Please watch carefully how to find the total number of terms divisible by 7. It will help you for the similar problems.
Great ! I hope now you understand the concept to find the total number of terms. It was really easy as you are thinking now.
Steps to Find Total Number of Terms Divisible 7
1. First we have to find the first three digit number divisible by 7. We can get it by dividing 100 by 7 and subtracting remainder from 100 result the highest two digit number multiple of 7. Now will add the 7 to 2 digit highest multiple of 7 that is 98 +7 = 105.
2. Again we have to find the highest or last 3 digit number multiple of 7. We can find it simply by dividing 1000 by 7 and subtracting the remainder from 1000 that is 1000 – 6 = 994.
3. Now make the arithmetic sequence of 3 digit number divisible by 7, first term as 105 and last term as 994.
4. Apply the nth term formula to last term of new arithmetic progression we made in step3. We will get the value of n . That is exactly the total 3 digit numbers divisible by 7.
Well dear ! Here are some few exercise related to above problems. Please try to solve these it will make you confident in nth term related problems.
Q1. How many two digits number are divisible by 7? ( Ans = 13)
Q2. Find the number of integers between 50 and 500 which are divisible by 7. (Ans = 64 )